If it's not what You are looking for type in the equation solver your own equation and let us solve it.
7x^2-3=340
We move all terms to the left:
7x^2-3-(340)=0
We add all the numbers together, and all the variables
7x^2-343=0
a = 7; b = 0; c = -343;
Δ = b2-4ac
Δ = 02-4·7·(-343)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9604}=98$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-98}{2*7}=\frac{-98}{14} =-7 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+98}{2*7}=\frac{98}{14} =7 $
| 8r+14r=88 | | 16x+4=20x+5 | | 3|y+4=30 | | -2(r+5=-31 | | 3x+7=14x+7 | | 3.8z=4.1z+10.5 | | 14=u/2+10 | | |4x-11|=-34 | | 5^2x-5^x=600 | | 3|y+4|=30 | | 50-4.95x=30-2.50x | | 12x-10=8x-30 | | 50+4.95x=30+2.50x | | 3v−6=−21 | | 2x−5=7 | | 3x+2+2x-7=135 | | 5x-14=-25 | | 1x+4=6x+5 | | X+3=5x-16 | | 6(y+2)=-2(4y-3)+2y | | x=1=9 | | 16=-8z-4z | | 30+40x=50x | | x=3(180-x)-17=100 | | 22x-3+4x=27 | | x=3(180-x)+17=100 | | 10=5/8x | | 2.2x-3+4x=27 | | 2x-5+x+3=5x-16 | | -16+3h=2 | | x=3(180-x)+100=17 | | 20m+4m=60-2m;10 |